在以下四种遍历过程中,前两种会抛出ConcurrentModificationException,而后两种方法是正确的.
Department类: package com.sitinspring;
import java.util.ArrayList; import java.util.Iterator; import java.util.List; public class Department { private String name; private List<Member> memberSheet; public Department(String name) { this.name = name; } public void addMemer(Member member) { if (memberSheet == null) { memberSheet = new ArrayList<Member>(); } memberSheet.add(member); } public void printMemberSheet() { System.out.println("----部门" + name + "人员名单---"); for (Member member : memberSheet) { System.out.println(member); } } /** * 里面的四个清除过程请分别独立执行 * */ public void removeYoungerFromMemberSheet() { // 遍历一:这个处理会抛出java.util.ConcurrentModificationException for (Member member : memberSheet) { if (member.getAge() < 30) { memberSheet.remove(member); } } // 遍历二:这个处理也会抛出java.util.ConcurrentModificationException for (Iterator it = memberSheet.iterator(); it.hasNext();) { Member member = (Member) it.next(); if (member.getAge() < 30) { memberSheet.remove(member); } } // 遍历三:这个处理调用Iterator 本身的方法 remove(),会正常执行 for (Iterator it = memberSheet.iterator(); it.hasNext();) { Member member = (Member) it.next(); if (member.getAge() < 30) { it.remove(); } } // 遍历四:这个处理不依赖Iterator,也会正常执行 for (int i=0;i<memberSheet.size();i++) { Member member = memberSheet.get(i); if (member.getAge() < 30) { memberSheet.remove(member); } } } public String toString() { return name; } public String getName() { return name; } public static void main(String[] args) { Department resarchDept = new Department("研发部门"); resarchDept.addMemer(new Member("张三", 38)); resarchDept.addMemer(new Member("李四", 24)); resarchDept.addMemer(new Member("王五", 30)); resarchDept.addMemer(new Member("钱七", 22)); resarchDept.addMemer(new Member("孙八", 39)); resarchDept.addMemer(new Member("周九", 30)); resarchDept.removeYoungerFromMemberSheet(); resarchDept.printMemberSheet(); } } Member类: package com.sitinspring;
public class Member{ private String name; private int age; private Department department; public Member(String name,int age){ this.name=name; this.age=age; } public String toString(){ StringBuffer sb=new StringBuffer(); sb.append("员工名="+name); sb.append(" 年龄="+age); if(department!=null){ sb.append(" 所属部门="+department); } return sb.toString(); } public void changeNewDepartment(Department newDepartment) { department.removeMemer(name); newDepartment.addMemer(this); } public String getName() { return name; } public void setDepartment(Department department) { this.department = department; } } 为什么会发生这样的结果呢?这是因为 "当使用 fail-fast iterator 对 Collection 或 Map 进行迭代操作过程中尝试直接修改 Collection / Map 的内容时,即使是在单线程下运行, java.util.ConcurrentModificationException 异常也将被抛出。 Iterator 是工作在一个独立的线程中,并且拥有一个 mutex 锁。 Iterator 被创建之后会建立一个指向原来对象的单链索引表,当原来的对象数量发生变化时,这个索引表的内容不会同步改变,所以当索引指针往后移动的时候就找不到要迭代的对象,所以按照 fail-fast 原则 Iterator 会马上抛出 java.util.ConcurrentModificationException 异常。 所以 Iterator 在工作的时候是不允许被迭代的对象被改变的。但你可以使用 Iterator 本身的方法 remove() 来删除对象, Iterator.remove() 方法会在删除当前迭代对象的同时维护索引的一致性。" 上述这段资料来自http://hi.baidu.com/xjenator/blog/item/23b235a89041d4b0ca130c16.html. java.util包中很多迭代器都是所谓的fail-fast迭代器.这些迭代器如果发现集合被修改,而且不是通过迭代器本身,那么抛出一个异常进行清除-ConcurrentModificationException-从而避免不安全行为的发生. 因此,第三种采用it.remove();不会出现任何异常,而第四不依赖于Iterator而依赖于索引当然更不会出现异常. 代码下载: http://www./Files/sitinspring/ConcurrentModificationTest20071203210937.rar |
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