ajax学习笔记一:动态更改div位置a small program ,in order to update the the position of a div use javascrpt , simulate to the tooltip. function Button1_onclick(elem)
{ var offsetx = elem["offsetLeft"]; var offsety = elem["offsetTop"]; while(elem) { offsetx += elem["offsetLeft"]; offsety += elem["offsetTop"]; elem = elem.offsetParent; } document.getElementById("tooltip").style.left=offsetx+"px"; document.getElementById("tooltip").style.top=offsety+"px"; } |
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来自: yfm10 > 《JavaScript》