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压强与流速的关系计算

 ltbbl 2011-05-07


p = p0(1-v^2/a0^2)^1/2        (1)

式中: p0 _ 无流压强,p -- 压强,V _ 流速, α0 _ 无流声速
1标准大气压=101325牛顿/㎡

声速,空气(15340m/s

压强与流速的关系,做泰勒展开,取前两项,就是伯努里方程: 

(1/2)*V^2 +(p/ p0)* a0^2= a0^2     (2)

设流速5m/s,算出p=101303牛顿/㎡,压强差p0- p=22牛顿/㎡

两个公式算出的结果对照如下:

V = 0,0.1 a0 ,0.2 a0 ,0.3 a0,0.4 a0,0.5 a0,…

P = p0 , 0.995 p0  ,0.980 p0  ,0.954 p0 ,0.917 p0 ,0.866 p0 ,…

P = p0  ,0.995 p0 ,0.980 p0  0.955 p0 ,0.920 p0 ,0.875 p0 ,…

p0 – p = 0 ,0.005 p0  ,0.020 p0 ,0.046 p0 ,0.083 p0 ,0.134 p0 ,…

p0 – p = 0,0.005 p0  ,0.020 p0 , 0.04 5 p0 ,0.080 p0 ,0.125 p0 ,…

中学流体知识,只定性不定量的历史,应结束。

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