配色: 字号:
1+1/(1+2)+1/(1+2+3)+...1/(1+2+..+n)
2012-05-31 | 阅:  转:  |  分享 
  
//求e.cpp:Definestheentrypointfortheconsoleapplication.



//e=1+1/(1+2)+1/(1+2+3)...1/(1+2+3+4...+n)

#include

#include

usingnamespacestd;

intmain(intargc,charargv[])

{

doublef(intn);

inta,i;

doublesum1=0;

cout<<"请输入一个整数:"<
cin>>a;

for(i=1;i<=a;i++)

sum1+=f(i);

cout<<"sum="<
getch();

return0;

}

doublef(intn)

{

intj;

doublesum2=0;

for(j=1;j<=n;j++)

sum2+=j;

return(1.0/sum2);

}
献花(0)
+1
(本文系Honey_Dog首藏)