获取单个文件行数文件:test1.sh 行数:20 方法一awk '{print NR}' test1.sh|tail -n1 如图所示: 方法二awk 'END{print NR}' test1.sh 如图所示: 方法三grep -n "" test1.sh|awk -F: '{print '}|tail -n1 如图所示: 方法四sed -n '$=' test1.sh 如图所示: 方法五wc -l test1.sh 如图所示: 方法六#cat test1.sh |wc -l 如图所示: 获取特定目录所有文件的行数代码如下: #!/bin/bash filesCount=0 linesCount=0 function funCount() { for file in ` ls $1 ` do if [ -d $1"/"$file ];then funCount $1"/"$file else declare -i fileLines fileLines=`sed -n '$=' $1"/"$file` let linesCount=$linesCount+$fileLines let filesCount=$filesCount+1 fi done } if [ $# -gt 0 ];then for m_dir in $@ do funCount $m_dir done else funCount "." fi echo "filesCount = $filesCount" echo "linesCount = $linesCount" 使用方法: 1、针对本目录 ./count.sh 2、统计多个目录 ./count.sh /tmp ~ 运行效果如下: 获取特定目录特定扩展名文件的行数代码如下: #!/bin/bash extens=(".c" ".cpp" ".h" ".hpp") filesCount=0 linesCount=0 function funCount() { for file in ` ls $1 ` do if [ -d $1"/"$file ];then funCount $1"/"$file else fileName=$1"/"$file EXTENSION="."${fileName##*.} echo "fileName = $fileName Extension = $EXTENSION" if [[ "${extens[@]/$EXTENSION/}" != "${extens[@]}" ]];then declare -i fileLines fileLines=`sed -n '$=' $fileName` echo $fileName" : "$fileLines let linesCount=$linesCount+$fileLines let filesCount=$filesCount+1 fi fi done } if [ $# -gt 0 ];then for m_dir in $@ do funCount $m_dir done else funCount "." fi echo "filesCount = $filesCount" echo "linesCount = $linesCount" 使用方法: 1、针对本目录 ./count.sh 2、统计多个目录 ./count.sh /tmp ~ 运行效果如下: 好,就这些了,希望对你有帮助。 |
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