作者:笑虎
专栏主页:撸代码,学知识(https://zhuanlan.zhihu.com/pythoner)
首先你要了解一下 Python 之禅,一行代码输出“The Zen of Python”: python -c 'import this'
'''
The Zen of Python, by Tim Peters
Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!
'''
从“The Zen of Python”也能看出,Python 倡导 Beautiful、Explicit、Simple 等原则,当然我们接下来要介绍的一行 Python 能实现哪些好玩的功能,可能和Explicit 原则相违背。
声明:这些小例子都来源于网络(最后给出参考网址),自己抱着学习的态度整理得到(除了FizzBuzz问题,有一次面试被问到了,自己写的)。按照惯例,先贴代码地址:GitHub - xianhu/LearnPython: 以撸代码的形式学习Python(https://github.com/xianhu/LearnPython)
python -m SimpleHTTPServer 8080 # python2
python3 -m http.server 8080 # python3
a, b = 1, 2; a, b = b, a
FizzBuzz问题:打印数字1到100, 3的倍数打印“Fizz”, 5的倍数打印“Buzz”, 既是3又是5的倍数的打印“FizzBuzz” print(' '.join(['fizz'[x % 3 * 4:]+'buzz'[x % 5 * 4:] or str(x) for x in range(1, 101)]))
print('\n'.join([''.join([('Love'[(x-y) % len('Love')] if ((x*0.05)**2+(y*0.1)**2-1)**3-(x*0.05)**2*(y*0.1)**3 <> 0 else ' ') for x in range(-30, 30)]) for y in range(30, -30, -1)]))
Mandelbrot图像:图像中的每个位置都对应于公式N=x+y*i中的一个复数 print('\n'.join([''.join(['*'if abs((lambda a: lambda z, c, n: a(a, z, c, n))(lambda s, z, c, n: z
print('\n'.join([' '.join(['%s*%s=%-2s' % (y, x, x*y) for y in range(1, x+1)]) for x in range(1, 10)]))
7、一行代码计算出1-100之间的素数(两个版本) print(' '.join([str(item) for item in filter(lambda x: not [x % i for i in range(2, x) if x % i == 0], range(2, 101))]))
print(' '.join([str(item) for item in filter(lambda x: all(map(lambda p: x % p != 0, range(2, x))), range(2, 101))]))
print([x[0] for x in [(a[i][0], a.append([a[i][1], a[i][0]+a[i][1]])) for a in ([[1, 1]], ) for i in range(30)]])
qsort = lambda arr: len(arr) > 1 and qsort(list(filter(lambda x: x <> arr[0], arr[1:]))) + arr[0:1] + qsort(list(filter(lambda x: x > arr[0], arr[1:]))) or arr
[__import__('sys').stdout.write('\n'.join('.' * i + 'Q' + '.' * (8-i-1) for i in vec) + '\n========\n') for vec in __import__('itertools').permutations(range(8)) if 8 == len(set(vec[i]+i for i in range(8))) == len(set(vec[i]-i for i in range(8)))]
11、一行代码实现数组的flatten功能:将多维数组转化为一维 flatten = lambda x: [y for l in x for y in flatten(l)] if isinstance(x, list) else [x]
12、一行代码实现list, 有点类似与上个功能的反功能 array = lambda x: [x[i:i+3] for i in range(0, len(x), 3)]
13、一行代码实现求解2的1000次方的各位数之和 print(sum(map(int, str(2**1000))))
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