首先,对令人讨厌的标题表示歉意.我稍后会更正.
我有一些如下数据
“ BOULEVARD”,“ BOUL”,“ BOULV”,“ BLVD”
我需要一个O(1)的数据结构来查找其他单词.例如,如果我使用字典,则需要存储这样的键/值,这对我来说很奇怪,
abbr.Add("BLVD", new List<string> { "BOULEVARD","BOUL","BOULV", "BLVD" });
abbr.Add("BOUL", new List<string> { "BOULEVARD", "BOUL", "BOULV", "BLVD" });
abbr.Add("BOULV", new List<string> { "BOULEVARD", "BOUL", "BOULV", "BLVD" });
abbr.Add("BOULEVARD", new List<string> { "BOULEVARD", "BOUL", "BOULV", "BLVD" });
使用哪种数据结构来使这些数据适合我的查询条件?
提前致谢 解决方法: 正如Petar Minchev所说,您可以将列表分为组列表和指向该组的键列表.为了简化此过程(使用),您可以编写自己的IDictionary实现并使用Add方法来构建这些组.我尝试了一下,它似乎起作用了.以下是实施的重要部分:
public class GroupedDictionary<T> : IDictionary<T,IList<T>>
{
private Dictionary<T, int> _keys;
private Dictionary<int, IList<T>> _valueGroups;
public GroupedDictionary()
{
_keys = new Dictionary<T, int>();
_valueGroups = new Dictionary<int, IList<T>>();
}
public void Add(KeyValuePair<T, IList<T>> item)
{
Add(item.Key, item.Value);
}
public void Add(T key, IList<T> value)
{
// look if some of the values already exist
int existingGroupKey = -1;
foreach (T v in value)
{
if (_keys.Keys.Contains(v))
{
existingGroupKey = _keys[v];
break;
}
}
if (existingGroupKey == -1)
{
// new group
int newGroupKey = _valueGroups.Count;
_valueGroups.Add(newGroupKey, new List<T>(value));
_valueGroups[newGroupKey].Add(key);
foreach (T v in value)
{
_keys.Add(v, newGroupKey);
}
_keys.Add(key, newGroupKey);
}
else
{
// existing group
_valueGroups[existingGroupKey].Add(key);
// add items that are new
foreach (T v in value)
{
if(!_valueGroups[existingGroupKey].Contains(v))
{
_valueGroups[existingGroupKey].Add(v);
}
}
// add new keys
_keys.Add(key, existingGroupKey);
foreach (T v in value)
{
if (!_keys.Keys.Contains(v))
{
_keys.Add(v, existingGroupKey);
}
}
}
}
public IList<T> this[T key]
{
get { return _valueGroups[_keys[key]]; }
set { throw new NotImplementedException(); }
}
}
用法如下所示:
var groupedDictionary = new GroupedDictionary<string>();
groupedDictionary.Add("BLVD", new List<string> {"BOUL", "BOULV"}); // after that three keys exist and one list of three items
groupedDictionary.Add("BOULEVARD", new List<string> {"BLVD"}); // now there is a fourth key and the key is added to the existing list instance
var items = groupedDictionary["BOULV"]; // will give you the list with four items
当然,实现整个接口需要大量工作,但是完成后,您将不必担心封装的类. 来源:https://www./content-1-542601.html
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