分享

《測圓海鏡》﹝諸差7﹞之明雙差、 雙差等式說

 瀟湘館112 2021-03-03

測圓海鏡諸差7﹞之明雙差*雙差等式

上傳書齋名:瀟湘館112  Xiāo Xiāng Guǎn 112

何世強 Ho Sai Keung

提要:《測圓海鏡》乃金‧李冶所撰,其書之“圓城圖式”含十四勾股形,連同原有之大勾股形共十五勾股形。本文著重明雙差*雙差之相關等式及其証明

關鍵詞:明雙差*雙差明差虛黃極雙差

《測圓海鏡》乃金‧李冶所撰,書成於 1248 年,時為南宋淳祐八年。該書卷一“圓城圖式”主要討論與十五勾股形相關之等式,本文介紹其部分等式並作出証明。

本文所引用之勾股式源自“圓城圖式”之十五勾股形,a1b1c1 乃最大勾股形天地乾之勾、股及弦長。故 a1b1c1 又稱為大勾﹝地乾﹞、大股﹝天乾﹞及大弦﹝天地﹞。

《測圓海鏡》涉及一系列之勾股恆等式,所有恆等式皆與十五勾股形有關。十五勾股形中最大者為天地乾,其三邊勾股弦分別以 a1b1c1 表之,其餘十四勾股形三邊勾股弦則分別以 aibici 表之,其中 1 < i 15。但 aibici 均可以 a1b1c1 表之,此乃《測圓海鏡》之精注意勾股定理成立,即  ai2 + bi2 = ci2

有關以 a1b1c1 aibici 之式可參閱筆者另文〈測圓海鏡》“圓城圖式”之十二勾股弦算法〉。

以下左為“圓城圖式”右為“圓城圖式十五句股形圖”

注意圓徑為 a1 + b1c1,見上圖之東南西北圓。圓徑乃十五勾股形三邊重要因子之一,其他因子為最大勾股形之勾股較、勾弦較及股弘較。

本文主要談及十五勾股形有三邊相差之等式,其中部分等式曾在“五和五較”等式中出現,可參閱筆者相關之文章。

注意等式 (c1b1)(c1a1) = (a1 + b1c1)2﹝雙差積圓徑平方半等式﹞。

本文取自《測圓海鏡‧卷一‧諸差》。筆者有以下之文涉及〈諸差〉

測圓海鏡大差差小差差等式﹝諸差1

測圓海鏡髙差旁差極雙差等式﹝諸差2

測圓海鏡極差等式﹝諸差3

測圓海鏡之角及虛差等式諸差 4

測圓海鏡諸差5﹞之髙差黃廣黃長等式

測圓海鏡諸差6﹞之邊弦底弦等式

本文乃以上六文之延續。

以下為有關明雙差”及“*雙差相關之等式:

明雙差亦為明*二大差其較則明差也*雙差亦為明*二小差其較則*差也明雙差內減明差即虛黃*雙差上加*差亦同上以明雙差加明和即兩明弦*雙差加*和則兩*弦也以明雙差減明和而半之即明黃又為虛大差*雙差減於*和而半之即*又為虛小差也以虛大差減明和即為明弦以虛小差減*和即*弦也明雙差*雙差相較則次差也明雙差*雙差相併,加於明*二和共則為兩個極雙差若以減於明*二和共則為兩個虛雙差也明雙差上加虛雙差即明*二股共*雙差上加虛雙即明*二勾共也

以下為各條目之証明:

明雙差亦為明*二大差

“明雙差”指明弦勾弦較明弦股弦較之和明弦在勾股形日月南 14

明弦勾弦較 = c14a14 =(b1 c1 + a1) (c1a1)2

明弦股弦 = c14 b14 =(c1a1)(b1 c1 + a1)(c1b1)

所以明雙差,即:

(b1 c1 + a1) (c1a1)2 + (c1a1)(b1 c1 + a1)(c1b1)

=(b1 c1 + a1) (c1a1)[(c1a1) + (c1b1)]

=(b1 c1 + a1) (c1a1) (2c1a1b1) #

明大差即明弦勾弦較 =(b1 c1 + a1) (c1a1)2

*大差*弦上勾弦= c15a15

c15a15 = (c1b1)(a1c1 + b1) – (c1b1)(a1c1 + b1)

= (c1b1)(c1a1)(b1 + a1c1)

= 明弦股弦較。

明大差+ *大差

= (b1 c1 + a1) (c1a1)2 + (c1b1)(c1a1)(b1 + a1c1)

= (b1 c1 + a1)(c1a1)[(c1a1) + (c1b1)]

=(b1 c1 + a1) (c1a1) (2c1a1b1) #

所以明弦勾弦較+ 明弦股弦 = 明大差 + *大差

其較則明差也

其較明弦勾弦較明弦股弦較之差,即:

(b1 c1 + a1) (c1a1)2(c1a1)(b1 c1 + a1)(c1b1)

=(b1 c1 + a1) (c1a1)[(c1a1) – (c1b1)]

=(b1 c1 + a1) (c1a1)(b1a1) #

明差”指明弦勾股較

明弦勾股較=b14a14= (c1a1)(b1 c1 + a1) –(c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[]

=(c1a1)(b1 c1 + a1)(b1a1) #

比較兩式可知相同,所以明雙差*二大差之差 = 明差

*雙差亦為明*二小差

*雙差”指*弦上勾弦較加*弦上股弦較。

*弦上勾弦= c15a15

= (c1b1)(a1c1 + b1) – (c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[ – 1]

= (c1b1)(b1 + a1c1)[c1a1]

= (c1b1)(c1a1)(b1 + a1c1)

*弦上股弦 = c15b15

c15b15= (c1b1)(a1c1 + b1) –(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[– 1]

= (c1b1)(a1c1 + b1)(c1b1)

= (c1b1)2(a1c1 + b1)

*弦上雙差

= (c1b1)(c1a1)(b1 + a1c1) + (c1b1)2(a1c1 + b1)

= (c1b1)(b1 + a1c1)[(c1a1) + (c1b1)]

=(c1b1)(b1 + a1c1)(2c1a1b1) #

明小差即明弦股弦 = c14 b14

c14 b14= (c1a1)(b1 c1 + a1) – (c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[– 1]

=(c1a1)(b1 c1 + a1)(c1b1)

*小差”指*弦上股弦 = c15b15

c15b15= (c1b1)(a1c1 + b1) –(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[– 1]

= (c1b1)(a1c1 + b1)(c1b1)

= (c1b1)2(a1c1 + b1)

明小差 + *小差,即:

(c1a1)(b1 c1 + a1)(c1b1) + (c1b1)2(a1c1 + b1)

= (b1 c1 + a1)(c1b1)[(c1a1) + (c1b1)]

= (b1 c1 + a1)(c1b1)(2c1a1b1) #

比較兩式可知相同,所以*雙差 = *二小差

其較則*差也

“其較”*雙差之較 = *勾弦較 *股弦較

= (c15a15) – (c15b15)

= c15a15c15 + b15

= b15a15

以上即*,即*弦上勾股較。

*弦上勾股= b15a15

= (c1b1)(a1c1 + b1) – (c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)()

=(c1b1)(a1c1 + b1)(b1a1) #

明雙差內減明差即虛黃

明雙差= 明弦股弦 + 明弦 = (c14 b14) + (c14 a14)

明差= b14 a14

明雙差內減明差即(c14 b14) + (c14 a14)– (b14 a14)

= c14 b14 + c14a14b14 + a14

= 2(c14b14)

= 2 ×(c1a1)(b1 c1 + a1)(c1b1) ﹝見前條﹞

=(c1a1)(b1 c1 + a1)(c1b1)

虛黃”即太虛弦三事= 弦和較 = b13 + a13c13

       c13 + b13 + a13

= – (c1b1)(c1a1) +(c1b1)(c1a1) + (c1b1)(c1a1)

=(c1b1)(c1a1)(– c1 + b1 + a1)

=(a1 + b1c1)2(– c1 + b1 + a1) ﹝雙差積圓徑平方半等式﹞。

所以明雙差內減明差 = 虛黃

*雙差上加*差亦同上

*雙差上加*= *勾弦較 + *股弦較 + *勾股較

= (c15a15) + (c15b15) + (b15a15)

= c15a15 +c15b15 + b15a15

= 2(c15a15)

= 2 ×(c1b1)(c1a1)(b1 + a1c1)﹝見前條﹞

= (c1b1)(c1a1)(b1 + a1c1)

此式同上。

以明雙差加明和即兩明弦

已知明弦在勾股形日月南 14勾弦較=c14a14

c14a14 = (c1a1)(b1 c1 + a1) –(c1a1)(b1 c1 + a1)

=(c1a1)(b1 c1 + a1)[– 1]

=(b1 c1 + a1)(c1a1)(c1a1)

=(b1 c1 + a1) (c1a1)2

明弦股弦 = c14 b14

= (c1a1)(b1 c1 + a1) – (c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[– 1]

=(c1a1)(b1 c1 + a1)(c1b1)

所以明雙差

=(b1 c1 + a1) (c1a1)2 + (c1a1)(b1 c1 + a1)(c1b1)

=(b1 c1 + a1) (c1a1)[(c1a1) + (c1b1)]

=(b1 c1 + a1) (c1a1)(2c1a1b1)

已知“明和”即明弦勾股和

明弦勾股和=b14 + a14 = (c1a1)(b1 c1 + a1) +(c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[+]

=(c1a1)(b1 c1 + a1)(a1 + b1)

明雙差加明和

=(c1a1)(b1 c1 + a1)(a1 + b1) + (b1 c1 + a1)(c1a1)(2c1a1b1)

= (b1 c1 + a1)(c1a1)[(a1 + b1) + (2c1a1b1)]

= (b1 c1 + a1)(c1a1) × 2c1

=(c1a1)(b1 c1 + a1)

已知 = c14 =(c1a1)(b1 c1 + a1)

兩明弦 = (c1a1)(b1 c1 + a1)

所以以明雙差加明和 = 兩明弦

另法:

明雙差+ 明和 = 明弦勾弦較 + 明弦股弦 + 明弦勾股和

= (c14a14) + (c14 b14) + (a14 + b14)

= c14a14 +c14 b14+ a14 + b14

= 2c14

以上即為兩明弦

*雙差加*和則兩*弦也

*雙差 + *= *弦勾弦較 +*弦股弦 + *弦勾股和

= (c15a15) + (c15 b15) + (a15 + b15)

= c15a15 +c15 b15+ a15 + b15

= 2c15

以上即為*。其以上之形式任何勾股形皆適用。

以明雙差減明和而半之即明黃又為虛大差

以明雙差減明和而半之

= (明和明雙差) = [明和 – (明弦勾弦較+ 明弦股弦)]

= {(a14+ b14)– [(c14a14) + (c14 b14)]}

= [a14 + b14(c14a14) – (c14 b14)]

= (a14 + b14c14 + a14c14 + b14)

= a14 + b14c14

以上即為明黃,或稱之為明黃方,又名明弦三事較,又名明弦弦和較。

明弦三事 = 弦和較 =b14 + a14 c14

b14 + a14 c14

= –(c1a1)(b1 c1 + a1) + (c1a1)(b1 c1 + a1) +
(c1a1)(b1 c1 + a1)

=(c1a1)(b1 c1 + a1)[ –++]

=(c1a1)(b1 c1 + a1)( – c1 + b1 + a1)

=(c1a1)(b1 c1 + a1)2

= (c1a1)(c1b1)(c1a1)

= (c1b1)(c1a1)2 #

虛大差”即太虛勾弦較

太虛勾弦較=c13a13= (c1b1)(c1a1) –(c1b1)(c1a1)

=(c1b1)(c1a1)[– 1]

=(c1b1)(c1a1)(c1a1)

=(c1b1)(c1a1)2 #

所以以明雙差減明和而半之 = 明黃 = 虛大差

*雙差減於*和而半之即*又為虛小差也

*雙差減*和而半之,即:

(**雙差) = [* – (*弦勾弦較 +*弦股弦)]

= {(a15+ b15)– [(c15a15) + (c15 b15)]}

= [a15 + b15(c15a15) – (c15 b15)]

= (a15 + b15c15 + a15c15 + b15)

= a15 + b15c15

以上即為***弦三事

*弦上三事較即*弦上弦和較 = (b15 + a15) – c15 = b15 + a15c15

b15 + a15c15

= –(c1b1)(a1c1 + b1) +(c1b1)(a1c1 + b1)
 +(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[ –+ +]

=(c1b1)(a1c1 + b1)( – c1 + b1 + a1)

=(c1b1)(a1c1 + b1)2

= (c1a1)(c1b1)(c1b1) ﹝雙差積圓徑平方半等式﹞

=(c1b1)2(c1a1) #

虛小差太虛股弦較

太虛股弦較= c13b13 = (c1b1)(c1a1) – (c1b1)(c1a1)

= (c1b1)(c1a1)[– 1]

= (c1a1)(c1b1)(c1b1)

= (c1a1)(c1b1)2 #

比較兩式,可知*弦上三事= 太虛上股弦較

以虛大差減明和即為明弦

已知虛大差太虛勾弦較,明和即明弦勾股和

明弦勾股和=b14 + a14 = (c1a1)(b1 c1 + a1) +(c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[+]

=(c1a1)(b1 c1 + a1)(a1 + b1)

太虛勾弦較=c13a13= (c1b1)(c1a1) –(c1b1)(c1a1)

=(c1b1)(c1a1)[– 1]

=(c1b1)(c1a1)(c1a1)

=(b1 c1 + a1)2(c1a1)

虛大差減明和,即:

(c1a1)(b1 c1 + a1)(a1 + b1) –(b1 c1 + a1)2(c1a1)

= (c1a1)(b1 c1 + a1)[(a1 + b1) – (b1 c1 + a1)]

= (c1a1)(b1 c1 + a1)(a1 + b1b1 + c1a1)

= (c1a1)(b1 c1 + a1) × c1

= (c1a1)(b1 c1 + a1) #

日月為明弦﹝簡﹞:c14 = (c1a1)(b1 c1 + a1) #

所以以虛大差減明和 = 明弦

以虛小差減*和即*弦也

虛小差”指太虛股弦較。

太虛股弦較= c13b13 = (c1b1)(c1a1) – (c1b1)(c1a1)

= (c1b1)(c1a1)[– 1]

= (c1a1)(c1b1)(c1b1)

= (c1a1)(c1b1)2

= (a1c1 + b1)2(c1b1) ﹝雙差積圓徑平方半等式﹞

*”指*弦上勾股和 = b15 +a15

b15 + a15 = (c1b1)(a1c1 + b1) +(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)(+)

= (c1b1)(a1c1 + b1)(b1 + a1)

以虛小差減*,即:

(c1b1)(a1c1 + b1)(b1 + a1) –(a1c1 + b1)2(c1b1)

=(c1b1)(a1c1 + b1)[(b1 + a1) – (a1c1 + b1)]

=(c1b1)(a1c1 + b1)(b1 + a1a1 + c1b1)

=(c1b1)(a1c1 + b1) × c1

= (c1b1)(a1c1 + b1) #

已知山川﹝簡﹞:c15 =(c1b1)(a1c1 + b1) #

所以以虛小差減* = *弦也

明雙差*雙差相較則次差也

已知明雙差 = (b1 c1 + a1)(c1a1)(2c1a1b1)

*弦上勾弦= c15a15

= (c1b1)(a1c1 + b1) – (c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[ – 1]

= (c1b1)(b1 + a1c1)[c1a1]

= (c1b1)(c1a1)(b1 + a1c1)

*弦上股弦 = c15b15

c15b15= (c1b1)(a1c1 + b1) –(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)[– 1]

= (c1b1)(a1c1 + b1)(c1b1)

= (c1b1)2(a1c1 + b1)

*弦上雙差,即:

(c1b1)(c1a1)(b1 + a1c1) + (c1b1)2(a1c1 + b1)

= (c1b1)(b1 + a1c1)[(c1a1) + (c1b1)]

=(c1b1)(b1 + a1c1)(2c1a1b1)

明雙差雙差,即:

(b1 c1 + a1) (c1a1) (2c1a1b1) –
(c1b1)(b1 + a1c1)(2c1a1b1)

=(b1 + a1c1)(2c1a1b1)[(c1a1) – (c1b1)]

=(a1 + b1c1)(2c1a1b1)[c1a1c1 + b1]

=(a1 + b1c1)(2c1a1b1)(b1a1) #

*二差共名次差

明差指明勾與明股之差,明勾與明股之式見前。

明差 = b14a14 = (c1a1)(b1 c1 + a1) – (c1a1)(b1 c1 + a1)

= (c1a1)( a1 + b1c1)[]

**勾與*股之差,*勾與*股之式亦見前。

* = b15a15 = (c1b1)(a1c1 + b1) – (c1b1)(a1c1 + b1)

=(c1b1)( a1 + b1c1) []

二差共 = 明差 + *

= (c1a1)( a1 + b1c1)[] + (c1b1)( a1 + b1c1) []

= ( a1 +b1c1)[](c1a1 + c1b1)

= (a1 + b1c1)(2c1a1b1) #

上式是為次差。故明雙差*雙差相較= 次差

明雙差*雙差併,加於明*二和共則為兩個極雙差

明雙差雙差共

=(b1 c1 + a1) (c1a1) (2c1a1b1) +
(c1b1)(b1 + a1c1)(2c1a1b1)

=(b1 + a1c1)(2c1a1b1)[(c1a1) + (c1b1)]

=(a1 + b1c1)(2c1a1b1)[c1a1b1 + c1]

=(a1 + b1c1)(2c1a1b1)2

已知明弦勾股和是為明和 = b14 + a14

b14 + a14 = (c1a1)(b1 c1 + a1) +(c1a1)(b1 c1 + a1)

= (c1a1)(b1 c1 + a1)[+]

=(c1a1)(b1 c1 + a1)(a1 + b1)

*弦上勾股和是為*= b15 + a15

b15 + a15 = (c1b1)(a1c1 + b1) +(c1b1)(a1c1 + b1)

= (c1b1)(a1c1 + b1)(+)

= (c1b1)(a1c1 + b1)(b1 + a1)

*二和共,即:

(c1a1)(b1 c1 + a1)(a1 + b1) + (c1b1)(a1c1 + b1)(b1 + a1)

= (b1 c1 + a1)(a1 + b1)[ (c1a1) + (c1b1)]

= (b1 c1 + a1)(a1 + b1)(2c1a1b1)

明雙差*雙差相並加於明*二和共,即:

(a1 + b1c1)(2c1a1b1)2+ (b1 c1 + a1)(a1 + b1)(2c1a1b1)

= (a1 + b1c1)(2c1a1b1)(2c1a1b1 + a1 + b1)

= (a1 + b1c1)(2c1a1b1) × 2c1

= (a1 + b1c1)(2c1a1b1) #

以下為勾弦差及股弦差:

c12a12 =(a1 + b1c1) –(a1 + b1c1) = (a1 + b1c1)[– 1]

c12b12 =(a1 + b1c1) –(a1 + b1c1) = (a1 + b1c1)[– 1]

雙差 = 即以上兩式之和,即:

(a1 + b1c1)[– 1] + (a1 + b1c1)[– 1]

= (a1 + b1c1)(c1a1) + (a1 + b1c1)(c1b1)

= (a1 + b1c1)(c1a1 + c1b1)

= (a1 + b1c1)(2c1a1b1)

兩個極雙差 上式乘以2= (a1 + b1c1)(2c1a1b1) #

所以明雙差 +*雙差 + *二和共 = 兩個極雙差

若以減於明*二和共則為兩個虛雙差也

明雙差*雙差相併,減於明*二和共,即:

(b1 c1 + a1)(a1 + b1)(2c1a1b1) –(a1 + b1c1)(2c1a1b1)2

= (a1 + b1c1)(2c1a1b1)( a1 + b1 – 2c1 + a1 + b1)

= (a1 + b1c1)2(2c1a1b1) × 2

= (a1 + b1c1)2(2c1a1b1) #

虛雙差”即太虛勾弦較太虛股弦較之和在勾股形月山泛 13

已知太虛勾弦較 = c13a13 = (c1b1)(c1a1) –(c1b1)(c1a1)

=(c1b1)(c1a1)[– 1]

= (c1b1)(c1a1)(c1a1)

= (c1b1)(c1a1)2

太虛股弦較= c13b13 = (c1b1)(c1a1) – (c1b1)(c1a1)

= (c1b1)(c1a1)[– 1]

= (c1a1)(c1b1)(c1b1)

= (c1a1)(c1b1)2

所以虛雙差 = (c1b1)(c1a1)2 + (c1a1)(c1b1)2

= (c1a1)(c1b1)[(c1a1) + (c1b1)]

= (c1a1)(c1b1)(2c1a1b1)

= (a1 + b1c1)2(2c1a1b1)

兩個虛雙差= (a1 + b1c1)2(2c1a1b1) #

所以明雙差*雙差相減於明*二和共 =兩個虛雙差

明雙差上加虛雙差即明*二股共 

已知明雙差 =(b1 c1 + a1)(c1a1)(2c1a1b1)

虛雙差 = (a1 + b1c1)2(2c1a1b1)

明雙差上加虛雙差=

(b1 c1 + a1) (c1a1) (2c1a1b1) +
 (a1 + b1c1)2(2c1a1b1)

= (a1 + b1c1)(2c1a1b1)[(c1a1) + (a1 + b1c1)]

= (a1 + b1c1)(2c1a1b1) × b1

= (a1 + b1c1)(2c1a1b1) #

已知日南﹝又﹞:b14 =(c1a1)(b1 c1 + a1)

山東﹝又﹞:b15 = (c1b1)(a1c1 + b1)

*二股共,即:

(c1a1)(b1 c1 + a1) + (c1b1)(a1c1 + b1)

= (a1 + b1c1)[(c1a1) + (c1b1)]

= (a1 + b1c1)(2c1a1b1) #

所以明雙差上加虛雙差 = *二股共

*雙差上加虛雙差即明*二勾共也

已知雙差 = (c1b1)(b1 + a1c1)(2c1a1b1)

虛雙差 = (a1 + b1c1)2(2c1a1b1)

*雙差上加虛雙差,即:

(c1b1)(b1 + a1c1)(2c1a1b1) +(a1 + b1c1)2(2c1a1b1)

= (b1 + a1c1)(2c1a1b1)[(c1b1) + (a1 + b1c1)]

= (b1 + a1c1)(2c1a1b1) × a1

= (b1 + a1c1)(2c1a1b1) #

已知南月勾﹝又﹞:a14 = (c1a1)(b1 c1 + a1)

東川勾﹝又﹞:a15 =(c1b1)(a1c1 + b1)

*二勾共 =a14 + a15 =

(c1a1)(b1 c1 + a1) + (c1b1)(a1c1 + b1)

= (b1 c1 + a1)[(c1a1) + (c1b1)]

= (b1 + a1c1)(2c1a1b1) #

所以*雙差上加虛雙差 = *二勾共

以下為測圓海鏡細草原文:

    转藏 分享 献花(0

    0条评论

    发表

    请遵守用户 评论公约

    类似文章