【原】c语言输出26进制1位数不等式公式代码正确版

​#include <stdio.h>

#include <stdlib.h>

int main()

{

char* a[18]={"i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

int i;

printf("\n输出18进制1位数字母不等式语句公式\n");

for(i=0;i<18;i++)

printf("%s!=i&&%s!=j&&%s!=k&&%s!=l&&%s!=m&&%s!=n&&%s!=o&&%s!=p&&%s!=q&&%s!=r&&%s!=s&&%s!=t&&%s!=u&&%s!=v&&%s!=w&&%s!=x&&%s!=y&&%s!=z&&\n",a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i]);

}

#include <stdio.h>

#include <stdlib.h>

int main()

{

char* a[26]={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

int i;

printf("\n输出26进制1位数字母不等式语句公式\n");

for(i=0;i<26;i++)

printf("%s!=a&&%s!=b&&%s!=c&&%s!=d&&%s!=e&&%s!=f&&%s!=g&&%s!=h&&%s!=i&&%s!=j&&%s!=k&&%s!=l&&%s!=m&&%s!=n&&%s!=o&&%s!=p&&%s!=q&&%s!=r&&%s!=s&&%s!=t&&%s!=u&&%s!=v&&%s!=w&&%s!=x&&%s!=y&&%s!=z&&\n",a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i],a[i]);

}