代码:
;***
;memcpy.asm - contains memcpy and memmove routines
;
; Copyright (c) 1986-1997, Microsoft Corporation. All right reserved.
;
;Purpose:
; memcpy() copies a source memory buffer to a destination buffer.
; Overlapping buffers are not treated specially, so propogation may occur.
; memmove() copies a source memory buffer to a destination buffer.
; Overlapping buffers are treated specially, to avoid propogation.
;
;*******************************************************************************
;***
;memcpy - Copy source buffer to destination buffer
;
;Purpose:
; memcpy() copies a source memory buffer to a destination memory buffer.
; This routine does NOT recognize overlapping buffers, and thus can lead
; to propogation.
; For cases where propogation must be avoided, memmove() must be used.
;
; Algorithm:
void* memcpy(void* dest, void* source, size_t count)
{
void* ret = dest;
//copy from lower address to higher address
while (count--)
*dest++ = *source;
return ret;
}
memmove
memmove - Copy source buffer to destination buffer
;
;Purpose:
; memmove() copies a source memory buffer to a destination memory buffer.
; This routine recognize overlapping buffers to avoid propogation.
; For cases where propogation is not a problem, memcpy() can be used.
;
; Algorithm:
void* memmove(void* dest, void* source, size_t count)
{
void* ret = dest;
if (dest <= source || dest >= (source + count))
{
//Non-Overlapping Buffers
//copy from lower addresses to higher addresses
while (count --)
*dest++ = *source++;
}
else
{
//Overlapping Buffers
//copy from higher addresses to lower addresses
dest += count - 1;
source += count - 1;
while (count--)
*dest-- = *source--;l
}
return ret;
}
另一种实现：
void* mymemcpy( void* dest, const void* src, size_t count )
{
char* d = (char*)dest;
const char* s = (const char*)src;
// int n = (count + 7) / 8; // count > 0 assumed
int n = count >> 3;
switch( count & 7 )
{
do { *d++ = *s++;
case 7: *d++ = *s++;
case 6: *d++ = *s++;
case 5: *d++ = *s++;
case 4: *d++ = *s++;
case 3: *d++ = *s++;
case 2: *d++ = *s++;
case 1: *d++ = *s++;
case 0 } //while (--n > 0);
while (n-- > 0)
}
return dest;
}
