大地坐标系(wgs84)转UTM

到现成的c#代码。。。
干脆自己根据一个网站上的js写了一个。

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001	class Program

002

{

003	static void Main(string[] args)

004

{

005	double[] utm = LatLonToUTM(30.65156708, 103.6880587);

006

}

007

008

009	static double pi = Math.PI;

010

011	static double sm_a = 6378137.0;

012	static double sm_b = 6356752.314;

013	//static double sm_EccSquared = 6.69437999013e-03;

014

015	static double UTMScaleFactor = 0.9996;

016	//得到的结果是：x坐标，y坐标，区域编号

017	public static double[] LatLonToUTM (double lat, double lon)

018

{

019	double zone = Math.Floor((lon + 180.0) / 6) + 1;

020

021	double cm = UTMCentralMeridian(zone);

022

023	double[] xy = new double[2];

024

025	MapLatLonToXY(lat / 180.0 * pi, lon / 180 * pi, cm, out xy);

026

027	/* Adjust easting and northing for UTM system. */

028	xy[0] = xy[0] * UTMScaleFactor + 500000.0;

029	xy[1] = xy[1] * UTMScaleFactor;

030	if (xy[1] < 0.0)

031

{

032	xy[1] = xy[1] + 10000000.0;

033

}

034

035	return new double[] { xy[0], xy[1], zone };

036

}

037

038	public static double UTMCentralMeridian (double zone)

039

{

040	double cmeridian;

041

042	double deg = -183.0 + (zone * 6.0);

043

044	cmeridian = deg / 180.0 * pi;

045

046	return cmeridian;

047

}

048

049	internal static void MapLatLonToXY (double phi, double lambda, double lambda0, out double[] xy)

050

{

051	double N, nu2, ep2, t, t2, l;

052	double l3coef, l4coef, l5coef, l6coef, l7coef, l8coef;

053	double tmp;

054

055	/* Precalculate ep2 */

056	ep2 = (Math.Pow(sm_a, 2.0) - Math.Pow(sm_b, 2.0)) / Math.Pow(sm_b, 2.0);

057

058	/* Precalculate nu2 */

059	nu2 = ep2 * Math.Pow(Math.Cos(phi), 2.0);

060

061	/* Precalculate N */

062	N = Math.Pow(sm_a, 2.0) / (sm_b * Math.Sqrt(1 + nu2));

063

064	/* Precalculate t */

065	t = Math.Tan (phi);

066	t2 = t * t;

067	tmp = (t2 * t2 * t2) - Math.Pow (t, 6.0);

068

069	/* Precalculate l */

070	l = lambda - lambda0;

071

072	/* Precalculate coefficients for l**n in the equations below

073	so a normal human being can read the expressions for easting

074	and northing

075	-- l**1 and l**2 have coefficients of 1.0 */

076	l3coef = 1.0 - t2 + nu2;

077

078	l4coef = 5.0 - t2 + 9 * nu2 + 4.0 * (nu2 * nu2);

079

080	l5coef = 5.0 - 18.0 * t2 + (t2 * t2) + 14.0 * nu2

081	- 58.0 * t2 * nu2;

082

083	l6coef = 61.0 - 58.0 * t2 + (t2 * t2) + 270.0 * nu2

084	- 330.0 * t2 * nu2;

085

086	l7coef = 61.0 - 479.0 * t2 + 179.0 * (t2 * t2) - (t2 * t2 * t2);

087

088	l8coef = 1385.0 - 3111.0 * t2 + 543.0 * (t2 * t2) - (t2 * t2 * t2);

089

090	/* Calculate easting (x) */

091

092	xy = new double[2];

093	xy[0] = N * Math.Cos (phi) * l

094	+ (N / 6.0 * Math.Pow (Math.Cos (phi), 3.0) * l3coef * Math.Pow (l, 3.0))

095	+ (N / 120.0 * Math.Pow(Math.Cos(phi), 5.0) * l5coef * Math.Pow(l, 5.0))

096	+ (N / 5040.0 * Math.Pow(Math.Cos(phi), 7.0) * l7coef * Math.Pow(l, 7.0));

097

098	/* Calculate northing (y) */

099	xy[1] = ArcLengthOfMeridian (phi)

100	+ (t / 2.0 * N * Math.Pow(Math.Cos(phi), 2.0) * Math.Pow(l, 2.0))

101	+ (t / 24.0 * N * Math.Pow(Math.Cos(phi), 4.0) * l4coef * Math.Pow(l, 4.0))

102	+ (t / 720.0 * N * Math.Pow(Math.Cos(phi), 6.0) * l6coef * Math.Pow(l, 6.0))

103	+ (t / 40320.0 * N * Math.Pow(Math.Cos(phi), 8.0) * l8coef * Math.Pow(l, 8.0));

104

105

return;

106

}

107

108	internal static double ArcLengthOfMeridian(double phi)

109

{

110	double alpha, beta, gamma, delta, epsilon, n;

111	double result;

112

113	/* Precalculate n */

114	n = (sm_a - sm_b) / (sm_a + sm_b);

115

116	/* Precalculate alpha */

117	alpha = ((sm_a + sm_b) / 2.0)

118	* (1.0 + (Math.Pow(n, 2.0) / 4.0) + (Math.Pow(n, 4.0) / 64.0));

119

120	/* Precalculate beta */

121	beta = (-3.0 * n / 2.0) + (9.0 * Math.Pow(n, 3.0) / 16.0)

122	+ (-3.0 * Math.Pow(n, 5.0) / 32.0);

123

124	/* Precalculate gamma */

125	gamma = (15.0 * Math.Pow(n, 2.0) / 16.0)

126	+ (-15.0 * Math.Pow(n, 4.0) / 32.0);

127

128	/* Precalculate delta */

129	delta = (-35.0 * Math.Pow(n, 3.0) / 48.0)

130	+ (105.0 * Math.Pow(n, 5.0) / 256.0);

131

132	/* Precalculate epsilon */

133	epsilon = (315.0 * Math.Pow(n, 4.0) / 512.0);

134

135	/* Now calculate the sum of the series and return */

136	result = alpha

137	* (phi + (beta * Math.Sin (2.0 * phi))

138	+ (gamma * Math.Sin(4.0 * phi))

139	+ (delta * Math.Sin(6.0 * phi))

140	+ (epsilon * Math.Sin(8.0 * phi)));

141

142	return result;

143

}

144

145

}