js 判断所选时间(或者当前时间)是否在某一时间段（转）

 1 var time_range = function (beginTime, endTime, nowTime) {
 2     var strb = beginTime.split (":");
 3     if (strb.length != 2) {
 4         return false;
 5     }
 6 
 7     var stre = endTime.split (":");
 8     if (stre.length != 2) {
 9         return false;
10     }
11 
12     var strn = nowTime.split (":");
13     if (stre.length != 2) {
14         return false;
15     }
16     var b = new Date ();
17     var e = new Date ();
18     var n = new Date ();
19 
20     b.setHours (strb[0]);
21     b.setMinutes (strb[1]);
22     e.setHours (stre[0]);
23     e.setMinutes (stre[1]);
24     n.setHours (strn[0]);
25     n.setMinutes (strn[1]);
26 
27     if (n.getTime () - b.getTime () > 0 && n.getTime () - e.getTime () < 0) {
28         return true;
29     } else {
30         alert ("当前时间是：" + n.getHours () + ":" + n.getMinutes () + "，不在该时间范围内！");
31         return false;
32     }
33 }
34 time_range ("21:30", "23:30", "3:22");

 

效果:

 

当前时间的情况下:

 1 var time_range = function (beginTime, endTime) {
 2     var strb = beginTime.split (":");
 3     if (strb.length != 2) {
 4         return false;
 5     }
 6 
 7     var stre = endTime.split (":");
 8     if (stre.length != 2) {
 9         return false;
10     }
11 
12     var b = new Date ();
13     var e = new Date ();
14     var n = new Date ();
15 
16     b.setHours (strb[0]);
17     b.setMinutes (strb[1]);
18     e.setHours (stre[0]);
19     e.setMinutes (stre[1]);
20 
21     if (n.getTime () - b.getTime () > 0 && n.getTime () - e.getTime () < 0) {
22         return true;
23     } else {
24         alert ("当前时间是：" + n.getHours () + ":" + n.getMinutes () + "，不在该时间范围内！");
25         return false;
26     }
27 }
28 time_range ("21:30", "23:30");

转自:http://www.cnblogs.com/vincent_ds/archive/2012/09/13/2683755.html