问题:分解因式:x²y-y²z+z²x-x²z+y²x+z²y-2xyz
解答:x²y-y²z+z²x-x²z+y²x+z²y-2xyz
=(x²y+y²x)+(z²x+z²y)-(y²z+x²z+2xyz )
=xy(x+y)+z²(x+y)-z(x+y)2
=(x+y)(xy+z²-zx-zy)
=(x+y)[x(y-z)-z(y-z)]
=(x+y)(y-z)(x-z)
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