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η(z)函数的欧拉积分式

 toujingshuxue 2018-08-06

(1)a>0:(z=a+bi)

        η(z)=(n=1…∞)(-1)n-1n-z.

(2)a>-1:

        η(z)=1/2+z(1,∞)A1(x)x-z-1dx

              其中,A1(x)=(-1/2)cos([x]π)

(3)a>-2:

        η(z)=1/2-A2(1)z+z(z+1)(1,∞)A2(x)x-z-2dx

              其中,A2(x)=A1(x)(x-[x]-1/2)

                                =(1/2)|y|-1/4

                             y=x-2[x/2]-1

(4)a>-3:

        η(z)=1/2-A2(1)z-A3(1)z(z+1)+z(z+1)(z+2)(1,∞)A3(x)x-z-3dx

其中,A3(x)=(1/4)y|y|-(1/4)y

 

······依此类推

 

(二)Ak(x)的求法:

(1)A2(x)=f2(y)=(1/2)|y|-1/4        →A2(2)=A2(0)=f2(1)=f2(-1)=1/4

(2)f3(y)=f3(-1)+ (-1,y)f2(y)dy

               =(1/4)y|y|-(1/4)y+f3(-1)        →A3(2)=A3(0)=f3(1)=f3(-1)

(3)f4(y)=f4(-1)+(-1,y)f3(y)dy

               =(1/12)y2|y|-(1/8)y2+f3(-1)y+1/24+f4(-1)       

        由f4(1)=f4(-1)得:f3(-1)=0

         ∴    A3(x)=f3(y)=(1/4)y|y|-(1/4)y

 

······依此类推

 

(二)Ak(x)的三角级数:

(1)A1(x)=(-2/π)(n=1…∞)(2n-1)-1sin(2n-1)πx(x≠整数)

(2)A2m(x)=(-1)m-1(2/π2m)(n=1…∞)(2n-1)-2m]cos(2n-1)πx(m=正整数)

(3)A2m+1(x)=(-1)m-1(2/π2m+1)(n=1…∞)(2n-1)-2m-1sin(2n-1)πx(m=正整数)

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